FP1 Topic 1: Inequalities
Modulus inequalities 1
|ax2+bx+c| > dx+e
The graph of y=2x+2 is shown in blue. The graph of y = |x2-1| is also shown. but where |x2-1| > 2x+2 the graph is red, otherwise it is green. Therefore the solution to |x2-1| > 2x+2 is x<-1 and x>3 Change the values of a, b, c, d or e and solve |ax2+bx+c| > dx+e

Summary In solving |ax2+bx+c| > dx+e, you need to solve |ax2+bx+c| = dx+e first Based on free Java applets from JavaMath