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Select the
Y= screen: For a general cubic graph, enter Y1 = AX^3+BX +CX+D Then select the GRAPH screen. You can then
choose different values for the constants A, B, C and D.
Alternatively,
enter Y1 = X-A
X-B
X-C Then
select the GRAPH screen. You can then choose different values for the
constants A, B and C.
For a general modulus graph, enter Y1 =
abs MX+C (Find abs in the CATALOG menu) Then select the
GRAPH screen. You can then choose different values for the constants M
and C.
To change the value of any of the constants, for example to make
M = 1, press 1
ALPHA M.
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The TI 82/3 can display the "gradient function" or
derivative of a curve. In other words, given the curve y=f(x), the curve
dy/dx=f'(x) (where f'(x) is the derivative of f(x) with respect to x) can be
displayed simultaneously. To set this up, go to the Y= screen. Against Y1=
enter a simple curve, 3x²+1 for example. Against Y2= you should make the
following selections: MATH 8 VARS Y-VARS 1 1 then type in ,X,X)
The result should be that the Y= screen shows Y1=3x²+1 and
Y2=nDerive(Y1,X,X). Go to the GRAPH screen, to see the graphs of
y=3x²+1 and the gradient function y=6x. If now you change the equation
against Y1, the calculator will automatically show its
derivative.
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The special
statistical functions on a TI-83 are most easily found by using the
CATALOG function (2nd 0).
Normal
probabilities Suppose that X ~ N(0,1), the standard normal
distribution: P(X < 0.2) is given by normalcdf(-1E99,0.2)
=.5792596878 P(-0.1 < X < 0.3) is given by normalcdf(-0.1,0.2)
=.119087584 If P(X < z) = 0.7, then z is given by invNorm(0.7) =
.5244005101
Suppose this question was
asked: IQ scores are assumed to be normally distributed with mean 100 and
standard deviation 15. Find the percentage of people expected to have an IQ
between 80 and 120. X ~ N(100,15²), so P(80<X<120) is given
by: normalcdf(80,120,100,15) = .8175774363.
ShadeNorm(80,120,100,15) displays the distribution and the
probability too
Binomial
probabilities Suppose that X ~ B(12,0.2): P(X=4) is given by
binompdf(12,0.2,4)=.1328755507 P(X
£ 4) is given by
binomcdf(12,0.2,4)=.9274445005 A list of all the probabilites
for the distribution B(12,0.2) is given by
binompdf(12,0.2)
Poisson
probabilities Suppose that X ~ P(5): P(X=2) is given by
poissonpdf(5,2)=.0842243375 P(X
£ 2) is given by
poissoncdf(5,2)=.1246520195
Using STAT
LIST
A complete set of
probabilities can be calculated at once and displayed in a list format. For
example: Suppose that X ~ B(5,0.5). Select the STAT LIST option and
enter the numbers 0,1,2,3,4,5 in list L1. Next enter binompdf(5,0.5,L1)
L2 and you will find all the probabilities P(X=0) to
P(X=5) displayed in list L2.
A
"Goodness of Fit" test As part of ASA2 module S3, you are
required to carry out a Goodness of fit, or c², test. The following data is thought to
from a Poisson distribution. Carry out a c² test to test this hypothesis.
| X |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
| O |
17 |
31 |
64 |
43 |
16 |
11 |
10 |
 Enter the above data into the first two
lists, and select STAT CALC 1. Enter L1, L2 so that the display shows
1-Var Stats L1,L2. The display will tell you that the mean,
l, of the distribution is 2.432291667. The
total frequency is 192. Now enter poissonpdf(2.43229, L1)
L3 to get the first display shown opposite. Next enter
L3 x 192
L4 and (L2-L4)²/L4
L5 to get the second display. Finally, LIST MATH 5 will
put sum( in the display. sum(L5) gives 15.15279386, which is the
c² test statistic to compare with the
relevant critical value.
Contingency
tables As part of ASA2 module S3, yo are required to carry out a
Goodness of fit, or c², test for a two-way
Contingency table. The whole process can be perfomed on the
calculator. The manager of a leasure centre collected data on the usage
of facilities in the centre by its members. Test if there is any association
between gender and type of facility used.
|
Pool |
Jacuzzi |
Gym |
TOTALS |
| Male |
35 |
31 |
54 |
120 |
| Female |
68 |
32 |
30 |
130 |
| TOTALS |
103 |
63 |
84 |
250 |
| 1. Select
MATRX EDIT, enter 2 x 3 and the data from the above table - not
including the totals. |
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| 2. Select
STAT TESTS C. this will bring up the c²-Test display showing the Observed data in
matrix A and Expected data in matrix B. Confirm by pressing enter and you will
get the results screen, showing the c²
test statistic and the degrees of freedom: |
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| 3. The
expected data is displayed by selecting MATRX EDIT 2. In this case the
5% critical value would be 5.991, meaning we have a significant result and
there is evidence of an association between gender and type of facility
used. |
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It is easy
to forget where these special functions are on you calculator. Check this
before your exam. |