| 1 |
If x2+4x-7 =
(x+p)2+q |
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A
p=-2, q=-3
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B
p=2, q=-3
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C
p=-2, q=3
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D
p=2, q=-11
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E
p=2, q=11
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| 2 |
If x2+4x+p =
(x+q)2+1 |
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A
p=1, q=2
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B
p=2, q=5
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C
p=5, q=2
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D
p=-1, q=5
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E
p=2, q=3
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| 3 |
The roots of
x2-3x-4=0 are: |
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| A 3,4 |
B -1,4 |
C 2,2 |
D 1,-4 |
E -1,-4 |
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| 4 |
The line of symmetry of y
= -(x+2)2-5 is |
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| A x = -2 |
B y = -5 |
C x = 2 |
D x = -5 |
E y = -2 |
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| 5 |
The zeros of the function
f(x)=x2-6 are |
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| A integers |
B irrational numbers |
C rational numbers |
D natural numbers |
E non-existant |
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| 6 |
Ö6 = |
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| A 2Ö3 |
B 3Ö2 |
C Ö2Ö3 |
D Ö(12)/2 |
E 3 |
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| 7 |
272/3=
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| A 18 |
B 6 |
C 81 |
D 3 |
E 9 |
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| 8 |
If f(x) =
x2-3x-5, then f(-1) = |
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| A -7 |
B -1 |
C -3 |
D -9 |
E 1 |
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| 9 |
If (x+2)(x-a) =
x2-4, then a = |
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| A -2 |
B 2 |
C 4 |
D -4 |
E 8 |
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| 10 |
The range of y =
-x2+6x-14 is |
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| A y³-14 |
B all real numbers |
C y³-5 |
D y£-5 |
E y£-14 |
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