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mean=41/20=2.05 The Binomial distribution requires two parameters, n and p. Assume n=4. Either estimate p from the above data (p=mean/n=0.5125) or use an assumed value. In the calculator, select You will find this in the and a sequence of the expected
frequencies will be displayed (here shown rounded to 1 dp): The Poisson distributionSuppose, instead, that you would like to fit a Poisson distribution to the above set of data. The Poisson distribution requires one paramenter, lambda. Assume lambda=2.05. In the calculator, select You will find this in the The Normal distributionYou can also calculate Normal probabilities easily. The Normal distribution requires two paramenters, mean and standard deviation. Assume mean=2.05 and standard deviation=2. To find the probability of a randomly selected value being less than, say, 3, (ie., the probabality P(X<3)), select You will find this in the If you wish to find probablities from the standard normal distribution, ie., N(0,1), then you can simply enter to find the probability P(Z<3). Here is a standard text book example on
Normal probabilities: Answer
Normal probabilities as areasThe above text book question could be answered using the ShadeNorm function instead (find this in theDISTR DRAW
menu, option 1):
Answer
Solving problems on the Normal distributionHere is another standard text book problem:An automatic filling machine is known to operate with a standard deviation of 1.5 g. To what "average filling" should the machine be set so that 95% of the packets are over 250g. Answer Use the invNorm function (in the Hence 1.644853626=-(250 - x)/1.5, which gives x=252.46...
Displaying probability distributions
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